8y^-3/2y^-7

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Solution for 8y^-3/2y^-7 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

y^-7*((8*y^-3)/2) = 0

4*y^-10 = 0 // : 4

y^-10 = 0

y naleu017Cy do O

y belongs to the empty set

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